- [游客] 功夫还是要下在平时啊。 06/16 11:36
- [crazyman] 改成0没问题，但是，不是最最合适的，这个题有分析才会让人更明白博主的思考结论。 06/08 18:01
- [crazyman] 回答正确。 06/08 17:59
- [beyond_alloo] 把1234改成零啊，呵呵，大意了 06/08 16:07
- [游客] 第（1）题不对。 06/08 14:25
- [游客] 对。 06/08 11:21
- [游客] 正确。 06/08 11:21
- [游客] 正确。 06/08 10:51
- [tomato] Right! 05/31 16:41
- [tomato] 第一题有不正确的地方，再看看改一下吧。 05/31 11:46
[2009-06-14 21:25] 要考试了
要考试了，好好复习，不然就要挂科了，呵呵。。。...
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[2009-06-08 16:01] 检测点 10.4 10.5
10.4 0bh
10.5 (1) 03h (2) ax = 1 bx = 0...
10.5 (1) 03h (2) ax = 1 bx = 0...
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[2009-06-06 22:52] 检测点 10.1 10.2 10.3
10.1
assume cs:code
stack segment
db 16 dup (0)
stack ends
code segment
start: mov ax, stack
mov ss, ax
mov sp, 10h
mov ax, 1000h
push ax
mov ax, 0h
push ax
retf
code ends
end start
10.2
ax 的值是 06h
10.3
ax 的值是 1010h...
assume cs:code
stack segment
db 16 dup (0)
stack ends
code segment
start: mov ax, stack
mov ss, ax
mov sp, 10h
mov ax, 1000h
push ax
mov ax, 0h
push ax
retf
code ends
end start
10.2
ax 的值是 06h
10.3
ax 的值是 1010h...
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[2009-06-06 11:23] 检测点 9.3
assume cs:code
code segment
start: mov ax, 2000h
mov ds, ax
mov bx, 0
s: mov cl, [bx]
mov ch, 0
inc cx
inc bx
loop s
ok: dec bx
mov dx, bx
mov ax, 4c00h
int 21h ; 程序返回
code ends
end start...
code segment
start: mov ax, 2000h
mov ds, ax
mov bx, 0
s: mov cl, [bx]
mov ch, 0
inc cx
inc bx
loop s
ok: dec bx
mov dx, bx
mov ax, 4c00h
int 21h ; 程序返回
code ends
end start...
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[2009-06-06 11:22] 检测点 9.2
assume cs:code
code segment
start: mov ax, 2000h
mov ds, ax
mov bx, 0
s: mov cx, 0
mov cl, [bx]
jcxz ok
inc bx
jmp short s
ok: mov dx, bx
mov ax, 4c00h
int 21h ; 程序返回
code ends
end start...
code segment
start: mov ax, 2000h
mov ds, ax
mov bx, 0
s: mov cx, 0
mov cl, [bx]
jcxz ok
inc bx
jmp short s
ok: mov dx, bx
mov ax, 4c00h
int 21h ; 程序返回
code ends
end start...
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[2009-06-06 10:11] 检测点 9.1
(1)
assume cs:code
data segment
dd 1234
data ends
code segment
start: mov ax, data
mov ds, ax
mov bx, 0
jmp word ptr [bx+1]
code ends
end start
(2)
assume cs:code
data segment
dd 12345678
data ends
code segment
start: mov ax, data
mov ds, ax
mov bx, 0
mov [bx], bx
mov ...
assume cs:code
data segment
dd 1234
data ends
code segment
start: mov ax, data
mov ds, ax
mov bx, 0
jmp word ptr [bx+1]
code ends
end start
(2)
assume cs:code
data segment
dd 12345678
data ends
code segment
start: mov ax, data
mov ds, ax
mov bx, 0
mov [bx], bx
mov ...
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[2009-05-27 20:39] 检测点 6.1
(1)
assume cs:codesg
codesg segment
dw 0123h, 0456h, 0789h, 0abch, 0defh, 0fedh, 0cbah, 0987h
start: mov ax, 0
mov ds, ax
mov bx, 0
mov cx, 8
s: mov ax, [bx]
mov cs:[bx], ax
add bx, 2
loop s
mov ax, 4c00h
int 21h
codesg ends
end start
(2)
assume cs:codesg
code...
assume cs:codesg
codesg segment
dw 0123h, 0456h, 0789h, 0abch, 0defh, 0fedh, 0cbah, 0987h
start: mov ax, 0
mov ds, ax
mov bx, 0
mov cx, 8
s: mov ax, [bx]
mov cs:[bx], ax
add bx, 2
loop s
mov ax, 4c00h
int 21h
codesg ends
end start
(2)
assume cs:codesg
code...
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[2009-05-23 10:59] 检测点 3.2
（1）
mov ax, 2000h
mov ss, ax
mov sp 0010h
(2)
mov ax, 1000h
mov ss, ax
mov sp 0000h...
mov ax, 2000h
mov ss, ax
mov sp 0010h
(2)
mov ax, 1000h
mov ss, ax
mov sp 0000h...
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[2009-05-23 00:32] 检测点 3.1
(1)
mov ax, 1
mov ds, ax
mov ax, [0000] ax = 2622
mov bx, [0001] bx = e626
mov ax, bx ax = e626
mov ax, [0000] ax = 2622
mov bx, [0002] bx = d6e6
add ax, bx ax = fdcc
add ax, [0004] ax = 2c98
mov ax, 0 ax = 0000
mov al, [0002] ax = 00e6
mov bx, 0 bx = 0000
mov bl, [000...
mov ax, 1
mov ds, ax
mov ax, [0000] ax = 2622
mov bx, [0001] bx = e626
mov ax, bx ax = e626
mov ax, [0000] ax = 2622
mov bx, [0002] bx = d6e6
add ax, bx ax = fdcc
add ax, [0004] ax = 2c98
mov ax, 0 ax = 0000
mov al, [0002] ax = 00e6
mov bx, 0 bx = 0000
mov bl, [000...
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[2009-05-20 12:53] 第二章
检测点 2.1
(1)
mov ax, 62627 ax = f4a3
mov ah, 31h ax = 31a3
mov al, 23h ax = 3123
add ax, ax ax = 6246
mov bx, 826ch bx = 826c
mov cx, ax cx = 6246
mov ax, bx ax = 826c
add ax, ax ax = 04d8
mov al, bh ax = 0482
mov ah, bl ax = 6c82
add ah, ah ax = d882
add al, 6 ...
(1)
mov ax, 62627 ax = f4a3
mov ah, 31h ax = 31a3
mov al, 23h ax = 3123
add ax, ax ax = 6246
mov bx, 826ch bx = 826c
mov cx, ax cx = 6246
mov ax, bx ax = 826c
add ax, ax ax = 04d8
mov al, bh ax = 0482
mov ah, bl ax = 6c82
add ah, ah ax = d882
add al, 6 ...
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