assume cs: code
a segment
dw 1,2,3,4,5,6,7,8
a ends
b segment
dw 0,0,0,0,0,0,0,0
b ends
code segment
start:
mov ax,a
mov ds,ax
mov ax,b
mov ss,ax
mov sp,10h ;因为b数据段的长度正好是10h，所以sp的值设置为10h
mov bx,0
mov cx ,8
s: push [bx]
add bx,2
loop s
...
- [游客] s: mov [bx], dx ---------------- 12/22 14:31
- [smxly53] 思考点光思考了。没记录下来，下次 12/10 11:42
- [游客] 还没有回答完全呢？后面还有思考点呢。 12/07 09:31
[2010-01-05 18:41] 实验5最后一题
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[2009-12-30 23:20] 实验5第5小题
assume cs:code
a segment
db 1,2,3,4,5,6,7,8
a ends
b segment
db 1,2,3,4,5,6,7,8
b ends
d segment
db 0,0,0,0,0,0,0,0
d ends
code segment
start:
mov ax,a
mov ds,ax
mov ax,b
mov es,ax
mov cx,8
mov bx,0
s1:
mov ax,es:[bx]
add ds:[bx],ax
...
a segment
db 1,2,3,4,5,6,7,8
a ends
b segment
db 1,2,3,4,5,6,7,8
b ends
d segment
db 0,0,0,0,0,0,0,0
d ends
code segment
start:
mov ax,a
mov ds,ax
mov ax,b
mov es,ax
mov cx,8
mov bx,0
s1:
mov ax,es:[bx]
add ds:[bx],ax
...
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[2009-12-19 01:05] 实验4.1 编程向内存0:200~0:23F依次传递0~63(3fh)
assume cs:code
code segment
mov ax, 0000h
mov ds, ax
mov bx,0200h
mov dx, 0h
mov cx,64
s: mov [bx], dx
inc dx
inc bx
loop s
mov ax, 4c00h
int 21h
code ends
end
结果：如上图...
code segment
mov ax, 0000h
mov ds, ax
mov bx,0200h
mov dx, 0h
mov cx,64
s: mov [bx], dx
inc dx
inc bx
loop s
mov ax, 4c00h
int 21h
code ends
end
结果：如上图...
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[2009-12-06 01:31] 汇编--53页检测点3.1 .2
CS=2000H,IP=0,DS=1000H,AX=0,BX=0
1> mov ax,6622H ;CS=2000H,IP=3,AX=6622H,BX=0
2> jmp 0ff0:0100 ;CS=0ff0,IP=0100H,AX=6622H,BX=0
3> mov ax,2000H ;CS=0ff0,IP=103,AX=2000H,BX=0
4> mov ds,ax; ds=ax=2000H,CS=0ff0,IP=105
5> mov ax,[0008] ;ax=c189,CS=0ff0,IP=108 ds=2000h...
1> mov ax,6622H ;CS=2000H,IP=3,AX=6622H,BX=0
2> jmp 0ff0:0100 ;CS=0ff0,IP=0100H,AX=6622H,BX=0
3> mov ax,2000H ;CS=0ff0,IP=103,AX=2000H,BX=0
4> mov ds,ax; ds=ax=2000H,CS=0ff0,IP=105
5> mov ax,[0008] ;ax=c189,CS=0ff0,IP=108 ds=2000h...
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