- [zyc969] 写第二空时的思维是正确的,但第一空是错误的,第二空必须用到第一空的数据,所以第二空也是错的。 我十 05/20 22:00
- [tomato] 两道题都做错了? 认真态度有待提高啊! 05/20 20:57
- [tomato] 是的,这本书就是要一字一句地读才行。 05/18 22:54
- [zyc969] 嗯,明白了。 05/18 13:46
- [tomato] 应该是第二道题做错了。 05/17 08:57
- [tomato] 学习质量第一。 05/15 23:22
- [tomato] 对了,博主的博客中没有动态显示,博主可以观察一下其它学习者的学习博客,好像是参加了汇编语言学习活动的 05/13 23:20
- [tomato] 做的没问题,不过,这才是第一章,当然还是比较简单的,虽然后面的章节也不难,难的是是否能够一直坚持下去 05/13 23:19
[2012-12-10 23:57] 实验11:编写子程序实现把所有小写字母转换成大字字母
data segment
db "Beginner's All-purpose Symbolic Instrution code.",0
data ends
stack segment
dw 16 dup (0)
stack ends
code segment
assume cs:code,ds:data,ss:stack
start:
mov ax,data
mov ds,ax
mov ax,stack
mov ss,ax
mov sp,32
mov...
[2013-07-05 20:24] 第六章检测点6.1作业
assume cs:codesg
codesg segment
dw 0123h,0456h,0789h,0abch,0defh,0fedh,0cbah,0987h
start:mov ax,0
mov ds,ax
mov bx,0
s:mov ax,[bx]
mov cs:[bx],ax
add bx,2
loop s
mov ax,4c00h
int 21h
codesg ends
end start
第二题:
assume cs:codesg
codesg segment
dw 0123h,0456...
[2013-07-05 08:40] 第五章实验4作业
assume cs:code
code segment
mov ax,20h
mov ds,ax
mov bl,0
mov cx,40h ;这个地方因为要导入40h(64)个数字,所以用40
s:mov al,bl
mov [bx],al
inc bx
loop s
mov ax,4c00h
int 21
code ends
end
第二题:
assume cs:code
code segment
mov ax,20h
mov ds,ax
mov bl,0
mov cx,40h ;这个地方因为要导入40h(64...
[2013-07-06 22:48] 第九章检测点9.2作业
code segment
start: mov ax,2000h
mov ds,ax
mov bx,0
s:mov ch,0
mov cl,[bx]
jcxz ok
inc bx
jmp short s
ok:mov dx,bx
mov ax,4c00h
int 21h
code ends
end start...
[2013-07-03 09:09] 第三章检测点3.1作业
mov ax,1
mov ds,ax
mov ax,[0000] ax=2662H
mov bx,[0001] bx=E626H
mov ax,bx ax=E626H
mov ax,[0000] ax=2662H
mov bx,[0002] bx=D6E6H
add ax,bx ax=FD48H
add ax,[0004] ax=2C14H
mov ax,0 ax=0000H
mov al,[0002] ax=OOE6H
mov bl,[000C] bx=D626H
add al,bl ax=001CH
第二题:
mov ax,6622 cs=20...
[2013-06-26 14:43] 第11章监测点11.1
zf=0 pf=0 sf=0
zf=0 pf=0 sf=0
zf=0 pf=0 sf=0
zf=0 pf=0 sf=0
zf=0 pf=1 sf=0
zf=0 pf=1 sf=1...
[2013-04-30 16:18] 汇编作业:实验4
codesg segment
mov ax,0020h
mov ds,ax
mov bx,0h
mov cx,40h
s:mov [bx],bx
inc bx
loop s
mov ax,4c00h
int 21h
codesg ends
end
2.assume cs:code
code segment
mov ax,cs
mov ds,ax
mov ax,0020h
mov es,ax
mov bx,0
mov cx,17h
s:mov al...
[2013-07-06 22:31] 第九章检测点9.1作业
assume cs:code
data segment
db 3 dup(0)
data ends
code segment
start: mov ax,data
mov ds,ax
mov bx,0
jmp word ptr [bx+1]
code ends
end start
第二题:
assume cs:code
data segment
dd 12345678h
data ends
code segment
start: mov ax,data
mov ds,ax
mov bx,0
mov [bx],bx
m...
[2013-07-04 08:56] 第三章实验二第一题作业
MOV DS,AX
MOV AX,2200
MOV SS,AX
MOV SP,0100
MOV AX,[0] ;AX=COEAH,
ADD AX,[2] ;AX=COFCH
MOV BX,[4] ;BX=30F0H
ADD BX,[6] ;BX=6021
PUSH AX ;SP=00FEH;修改的内存单元的地址是2200:00FE,内容为C0FCH
PUSH BX ;SP=00FCH;修改的内存单元的地址是2200:00FC,内容为6021H
POP AX ;SP=00fEH;AX=6021H
POP BX ;SP=0100H;BX=CO...
[2013-07-06 22:59] 第九章检测点9.3作业
code segment
start: mov ax,2000h
mov ds,ax
mov bx,0
s:mov cl,[bx]
mov ch,0
add cx,1 ;此处显示不能使用jcxz指令,否则后边的dec bx则一点意义都没有,而且多余
inc bx
loop s
ok:dec bx
mov dx,bx
mov ax,4c00h
int 21h
code ends
end start...
[2013-07-05 22:37] 第六章实验五作业
assume cs:code,ds:data,ss:stack
data segment
dw 0123h,0456h,0789h,0abch,0defh,0fedh,0cbah,0987h
data ends
stack segment
dw 0,0,0,0,0,0,0,0
stack ends
code segment
start: mov ax,stack
mov ss,ax
mov sp,16
mov ax,data
mov ds,ax
push ds:[0]
push ds:[2]
pop ds:[2]
pop ds...
[2013-04-20 14:04] 汇编作业2.3
1,2次在运行完指令后,3次是 jmp ax 运行的结果
IP=ax...
[2013-04-22 11:03] 汇编作业3.1
BX=E626
AX=E626
AX=2662
BX=D6E6
AX= FD48
AX=2C14
AX=0000
AX=00E6
BX=0000
BX=0026
AX=000C
2.MOV AX,6622 AX=6622 IP=3
JMP OFFO:0100 IP=8,IP=0100 CS=1000,IP=0000
MOV AX,2000 AX=2000 IP=3
MOV DS,AX DS=2000 IP=5
MOV AX,[0...
[2013-04-24 14:59] 汇编语言作业3.2
mov ds,ax
mov ax,2000
mov sp,0010
push [0]
push [2]
push [4]
push [6]
push [8]
push [A]
push [C]
push [E]
mov ax,2000
mov ds,2000
2. mov ax,2000
mov ds,ax
mov ax,1000
mov ss,ax
mov sp,0000
p...
[2013-04-18 14:28] 汇编作业1.1
2.1024, 0-1023
3.8192,1024
4.1024*1024*1024Byte,1024*1024Byte,1024Byte
5.64KB,1MB,16MB,4G
6.256B,256B,64kB,64KB,4G
7.1,1
8.二进制...
[2013-04-19 14:20] 汇编作业2.1
1.AX=62627
2.AX=3100h
3.AX=0023H
4.AX=6246H
5.BX=826CH
6.CX=6246H
7.AX=826CH
8.AX=04D8H
9.AX=0482H
10.AX=6C82H
11.AX=D882H
12.AX=D888H
13.AX=D910H
14.AX=3B56H
(2)
MOV AX,100H
ADD AX...
[2013-06-21 21:06] 课程设计1
datasg segment
db '1975','1976','1977','1978','1979','1980', '1981'
db '1982', '1983','1984', '1985','1986', '1987','1988'
db '1989','1990','1991','1992','1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479
dd 140417,197514,34...
[2013-07-06 10:54] 第八章实验7作业
data segment
;21年
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
;21的总收入
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,8...
[2013-05-15 20:39] 第8章实验7
datasg segment
db '1975','1976','1977','1978','1979','1980', '1981'
db '1982', '1983','1984', '1985','1986', '1987','1988'
db '1989','1990','1991','1992','1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,5...
[2013-04-19 16:38] 汇编作业2.2
2.2000H,2FFFH
3.当段地址小于2000H或大于2FFFH时,无法寻到20000H单元...