10.1显示字符串
assume cs:code
data segment
db 'welcome to masm!',0
data ends
code segment
start: mov dh,8
mov dl,3
mov cl,2
mov ax,data
mov ds,ax
mov si,0
call show_str
mov ah,1
int 21h
mov ax,4c00h
int 21h
show_str: mov ax,0b800h
mov es,ax
mov di,0
mov ah,cl
s: mov al,[si]
mov es:[di],ax
mov ch,[si]
mov cl,0
jcxz ok
inc si
add di,2
jmp short s
ok: ret
code ends
end start
10.2解决除法溢出
assume cs:code
code segment
start: mov ax,4240h
mov dx,000fh
mov cx,0ah
call divdw
mov ax,4c00h
int 21h
divdw: mov si,ax
mov ax,dx
mov dx,0
div cx
mov di,ax
mov ax,si
div cx
mov cx,dx
mov dx,di
ret
code ends
end start
10.3数值显示
assume cs:code
data segment
db 10 dup(0)
data ends
code segment
start: mov ax,12666
mov bx,data
mov ds,bx
mov si,1
call dtoc
mov dh,8
mov dl,3
mov cl,2
call show_str
mov ah,1
int 21h
mov ax,4c00h
int 21h
dtoc: mov bx,10
mov dx,0
div bx
add dl,30h
mov [si],dl
mov cx,ax
jcxz ok1
inc si
jmp short dtoc
ok1: ret
show_str:
dec dh
dec dl
mov al,160
mul dh
mov bx,ax
mov al,2
mul dl
add bx,ax
mov ax,0b800h
mov es,ax
mov di,bx
mov ah,cl
s: mov al,[si]
mov es:[di],ax
mov cx,si
jcxz ok2
dec si
add di,2
jmp short s
ok2: ret
code ends
end start
- [nbfengyi] 图在相册 10/22 22:02
- [nbfengyi] 图片在相册里 10/21 15:43
- [chinatree] 书上有讲。 10/04 12:30
- [12345678911] 第三问的解答我不懂什么回事能解释下吗 10/04 11:45
- [chinatree] 写出来就行了，不用太纠结。 09/29 21:00
- [nbfengyi] 用了一整个下午写这个程序，一开始就想到了循环，开始想外循环必有一次，内循环有4字节和2字节的，是不要 09/29 20:20
- [nbfengyi] 开始没有注意是四个字母 09/27 20:06
- [nbfengyi] 开始时： -d ds:0 144C:0000 31 2E 20 64 69 73 70 6C- 09/27 20:06
- [chinatree] 你不要拿半成品来糊弄自己好不好？！ 09/27 17:50
- [nbfengyi] 受教了， 09/24 09:59
