assume cs:code
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
stack segment
dw 0,0,0,0,0,0,0,0
stack ends
code segment
start: mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov ax,stack
mov ss,ax
mov sp,10h
mov di,0
mov bx,0
mov bp,0
mov cx,21
s: push cx
mov si,0
mov dx,0
mov cx,2
s1:
mov ax,ds:[di]
mov es:[si+bx],ax
mov ax,ds:[di+84]
mov es:[si+5+bx],ax
sub si,dx
mov al,ds:[bp+168]
mov es:[si+0ah+bx],al
add di,2
inc bp
inc si
inc dx
add si,dx
loop s1
push dx
mov ax,es:[1+bx+si]
mov dx,es:[3+bx+si]
div word ptr es:[bx+si+6]
mov es:[bx+si+9],ax
pop dx
add bx,16
pop cx
loop s
mov ax,4c00h
int 21h
code ends
end start
-d es:0
1459:0000 31 39 37 35 20 10 00 00-00 20 03 00 20 05 00 20 1975 .... .. ..
1459:0010 31 39 37 36 20 16 00 00-00 20 07 00 20 03 00 20 1976 .... .. ..
1459:0020 31 39 37 37 20 7E 01 00-00 20 09 00 20 2A 00 20 1977 ~... .. *.
1459:0030 31 39 37 38 20 4C 05 00-00 20 0D 00 20 68 00 20 1978 L... .. h.
1459:0040 31 39 37 39 20 56 09 00-00 20 1C 00 20 55 00 20 1979 V... .. U.
1459:0050 31 39 38 30 20 40 1F 00-00 20 26 00 20 D2 00 20 1980 @... &. ..
1459:0060 31 39 38 31 20 80 3E 00-00 20 82 00 20 7B 00 20 1981 .>.. .. {.
1459:0070 31 39 38 32 20 A6 5F 00-00 20 DC 00 20 6F 00 20 1982 ._.. .. o.
-d
1459:0080 31 39 38 33 20 91 C3 00-00 20 DC 01 20 69 00 20 1983 .... .. i.
1459:0090 31 39 38 34 20 C7 7C 01-00 20 0A 03 20 7D 00 20 1984 .|.. .. }.
1459:00A0 31 39 38 35 20 81 24 02-00 20 E9 03 20 8C 00 20 1985 .$.. .. ..
1459:00B0 31 39 38 36 20 8A 03 03-00 20 A2 05 20 88 00 20 1986 .... .. ..
1459:00C0 31 39 38 37 20 7C 47 05-00 20 D2 08 20 99 00 20 1987 |G.. .. ..
1459:00D0 31 39 38 38 20 EB 03 09-00 20 E9 0A 20 D3 00 20 1988 .... .. ..
1459:00E0 31 39 38 39 20 CA 42 0C-00 20 C5 0F 20 C7 00 20 1989 .B.. .. ..
1459:00F0 31 39 39 30 20 18 0D 12-00 20 03 16 20 D1 00 20 1990 .... .. ..
-d
1459:0100 31 39 39 31 20 38 1F 1C-00 20 22 20 20 E0 00 20 1991 8... " ..
1459:0110 31 39 39 32 20 58 19 2A-00 20 16 2D 20 EF 00 20 1992 X.*. .- ..
1459:0120 31 39 39 33 20 28 44 39-00 20 5E 38 20 04 01 20 1993 (D9. ^8 ..
1459:0130 31 39 39 34 20 28 F0 46-00 20 99 3B 20 30 01 20 1994 (.F. .; 0.
1459:0140 31 39 39 35 20 68 97 5A-00 20 88 45 20 4D 01 20 1995 h.Z. .E M.
- [nbfengyi] 图在相册 10/22 22:02
- [nbfengyi] 图片在相册里 10/21 15:43
- [chinatree] 书上有讲。 10/04 12:30
- [12345678911] 第三问的解答我不懂什么回事能解释下吗 10/04 11:45
- [chinatree] 写出来就行了,不用太纠结。 09/29 21:00
- [nbfengyi] 用了一整个下午写这个程序,一开始就想到了循环,开始想外循环必有一次,内循环有4字节和2字节的,是不要 09/29 20:20
- [nbfengyi] 开始没有注意是四个字母 09/27 20:06
- [nbfengyi] 开始时: -d ds:0 144C:0000 31 2E 20 64 69 73 70 6C- 09/27 20:06
- [chinatree] 你不要拿半成品来糊弄自己好不好?! 09/27 17:50
- [nbfengyi] 受教了, 09/24 09:59