assume cs:codesg
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
stack segment
dw 0,0,0,0,0,0,0,0
stack ends
codesg segment
start:mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov ax,stack
mov ss,ax
mov sp,10h
mov bp,0
mov bx,0
mov cx,21
s0: push cx
mov si,0
mov cx,4
s1: mov ax,[bx+si]
mov [bp+si],ax
inc si
loop s1
mov si,0
mov cx,4
s2: mov ax,[bx+54h+si]
mov [bp+5+si],ax
inc si
loop s2
mov ax,[bx+54h]
mov [bp+0ah],ax
mov ax,es:[bp+5]
mov dx,es:[bp+7]
div word ptr es:[bp+0ah]
mov es:[bp+0dh],ax
add bp,10h
add bx,4
pop cx
loop s0
mov ax,4c00h
int 21h
codesg ends
end start
改正后 还没调试 明天继续
assume cs:codesg
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
stack segment
dw 0,0,0,0,0,0,0,0
stack ends
codesg segment
start:mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov ax,stack
mov ss,ax
mov sp,10h
mov si,0
mov bp,0
mov bx,0
mov cx,21
s0: push cx
mov si,0
mov cx,4
s1: mov ax,ds:[bx+si]
mov es:[bp+si],ax
inc si
loop s1
mov si,0
mov cx,4
s2: mov ax,ds:[bx+54h+si]
mov es:[bp+5+si],ax
inc si
loop s2
mov ax,ds;[bx+0a8h]
mov es:[bp+0ah],ax
mov ax,es:[bp+5]
mov dx,es:[bp+7]
mov si,es:[bp+0ah]
div si
mov es:[bp+0dh],ax
add bp,10h
add bx,4
pop cx
loop s0
mov ax,4c00h
int 21h
codesg ends
end start
比较一下这两个程序
前一个div word ptr es:[bp+0ah]在执行后显示逸出(overflow)
后一个将其改为mov si,es:[bp+si] div si 程序就正常执行了
为什么? 请教高手了 书上有实例div word ptr es:[0] 第170页最上面
- [12sunfeng34] 哦 对 08/24 19:34
- [12sunfeng34] 对 (2)中的sp应该是0 谢谢 08/24 07:14
- [mess] 第一题注意段地址是1,即偏移地址为0时(取偏移地址最小值),物理地址=1*10h+0=10H 08/23 15:20
- [mess] sp都设置等于16,有问题。 08/23 15:19
- [mess] 把第一个答案转换成十六进制的。 学完第二章的实验,会了debug,可以用a命令写入指令,然后t 08/23 15:18
- [mywiil] 注意借鉴后的吸收哟。 08/21 03:29
- [12sunfeng34] 对应该是 我算错了 08/19 18:54
- [12sunfeng34] 谢谢 08/19 18:52
- [whfeiya] 这个好像不对吧,应该倒数第四个是D882,D888,D810 08/18 12:49
- [beichenyibei] 您好!我之前写错了,像“指令 寄存器,寄存器”这种形势的指令,每次读取后ip+2不是+3,。 像“ 08/17 10:05