- [zaixuexi] 我以为是a0=0,a1=1,没仔细看 02/12 09:23
- [yang5731] 不对吧 我的结果应该是对的 N=9时 确实得217 你自己算算。你帮我看看论坛 算法上的程序吧 题 02/11 23:49
- [zaixuexi] 递归不是这么写的哦,我想你肯定没调试过自己写的这代码. 先看C代码吧: unsigned int 02/11 22:58
- [游客] <a href="http://www.playren.com/">整人方法</a> 12/15 17:11
- [wisji8] mov ax,0a0h mul dh mov bx,ax mov ax,2 mul 10/03 16:56
- [yang5731] 谢谢了 课程设计一做出来了 确实不能调用着个····· 08/25 02:50
- [mywiil] 课程设计一要用到这个子程序，这里暂不做评论。 赶紧完成课程设计一吧。 08/21 03:33
[2010-08-07 02:08] 实验7 （用栈）
;有个疑惑，为什么用T命令执行pop [bx+2]后，
;Program terminated normally.程序好像直接运行完了，结果也正确
;------------------------------------------------------
assume cs:codesg
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
codesg segment
start: mov ax,data
mov ss,ax ;把data设成栈段
mov cx,15h
sub bx,bx
mov ax,table
mov ds,ax
a: pop [bx] ;[bx]的默认段为DS
pop [bx+2]
add bx,10h
loop a
mov cx,15h
sub bx,bx
b: pop [bx+5]
pop [bx+7]
add bx,10h
loop b
sub bx,bx
mov cx,15h
c: pop ds:[bx+10]
add bx,10h
loop c
sub bx,bx
mov cx,15h
d: mov ax,[bx+5]
mov dx,[bx+7]
mov di,[bx+10]
div di
mov [bx+13],ax
add bx,10h
loop d
mov ax,4c00h
int 21h
codesg ends
end start
;Program terminated normally.程序好像直接运行完了，结果也正确
;------------------------------------------------------
assume cs:codesg
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
codesg segment
start: mov ax,data
mov ss,ax ;把data设成栈段
mov cx,15h
sub bx,bx
mov ax,table
mov ds,ax
a: pop [bx] ;[bx]的默认段为DS
pop [bx+2]
add bx,10h
loop a
mov cx,15h
sub bx,bx
b: pop [bx+5]
pop [bx+7]
add bx,10h
loop b
sub bx,bx
mov cx,15h
c: pop ds:[bx+10]
add bx,10h
loop c
sub bx,bx
mov cx,15h
d: mov ax,[bx+5]
mov dx,[bx+7]
mov di,[bx+10]
div di
mov [bx+13],ax
add bx,10h
loop d
mov ax,4c00h
int 21h
codesg ends
end start
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[ 游客 发表于 2010-12-15 17:11 ]
<a href="http://www.playren.com/">整人方法</a>