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主题 : : 看看高手是怎么写试验7代码的！！！强烈推荐中... [待解决] |
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[帖 主] [ 发表时间：2008-10-10 02:55 ] | |
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注册日期：2008-09-03 00:18 |
DATAS SEGMENT
DB '1975', '1976', '1977', '1978', '1979', '1980', '1981', '1982'
DB '1983', '1984', '1985', '1986', '1987', '1988', '1989', '1990'
DB '1991', '1992', '1993', '1994', '1995'
DD 16, 22, 382, 1356, 2390, 8000, 16000, 24486, 50065, 97479, 140417, 197514
DD 345980, 590827, 803530, 118300, 184300, 2759000, 3753000, 4649000, 5937000
DW 3, 7, 9, 13, 28, 38, 130, 220, 476, 778, 1001, 1442, 2258, 2793, 4037, 5635, 8226
DW 11542, 14430, 15257, 17800
DATAS ENDS
TABLE SEGMENT
DB 21 DUP ('year summ ne ?? ')
TABLE ENDS
STACKS SEGMENT
DB 16 DUP (0)
STACKS ENDS
ASSUME CS:CODES,DS:DATAS,SS:STACKS
CODES SEGMENT
START:
;相关寄存器初始化
MOV AX,DATAS
MOV DS,AX
MOV AX,TABLE
MOV ES,AX
MOV AX,STACKS
MOV SS,AX
MOV SP,16
MOV BX,0
MOV BP,0
MOV DI,0
MOV SI,0
MOV CX,21
cycle: ;使用栈复制年份
PUSH [DI].0
PUSH [DI].2
POP ES:[BP].2
POP ES:[BP].0
;使用栈复制收入
PUSH 54H.[DI].0
PUSH 54H.[DI].2
POP ES:[BP].7
POP ES:[BP].5
;使用栈复制雇员数
PUSH 0A8H.[SI]
POP ES:[BP].0AH
;计算人均收入
MOV AX,ES:[BP].5
MOV DX,ES:[BP].7
DIV WORD PTR ES:[BP].0AH
MOV ES:[BP].0DH,AX
ADD SI,2H
ADD DI,4H
ADD BP,10H
loop cycle
MOV AH,4CH
INT 21H
CODES ENDS
END START
-------------------------------------------------------------------
栈的使用、结构化程序设计的思想...
话就不多说了，自己体会吧 | | |
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[第43楼] [ 回复时间：2010-09-23 19:30 ] | |
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注册日期：2010-09-19 19:28 |
assume cs:code
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
code segment
start:mov ax,data
mov ds,ax
mov ax,table
mov ss,ax
mov cx,15H
mov bp,0H
mov bx,0H
WS1: push cx
mov cx,4H
mov si,0H
NS1: mov al,ds:[bp+si]
mov ss:[bx+si],al
inc si
loop NS1
add bp,4
add bx,10H
pop cx
loop WS1
mov cx,15H
mov bp,54H
mov bx,0H
WS2: mov ax,ds:[bp]
mov ss:[bx+5],ax
mov ax,ds:[bp+2]
mov ss:[bx+7],ax
mov byte ptr ss:[bx+4],0
mov byte ptr ss:[bx+9],0
mov byte ptr ss:[bx+12],0
mov byte ptr ss:[bx+0fH],0
add bp,4H
add bx,10H
loop WS2
mov cx,15H
mov bp,0a8H
mov bx,0H
WS3: mov ax,ds:[bp]
mov ss:[bx+0aH],ax
add bp,2H
add bx,10H
loop WS3
mov cx,15H
mov bp,0
WS4: mov ax,[bp+5]
mov dx,[bp+2+5]
div word ptr [bp+10]
mov [bp+0dH],ax
add bp,10H
loop WS4
mov ax,4c00h
int 21h
code ends
end start | | |
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