大家看看我做的对不对,经过调试功能实现.只是觉得方法有前妥当.大家指点一二
assume cs:code
a segment
db 1,2,3,4,5,6,7,8
a ends
b segment
db 1,2,3,4,5,6,7,8
b ends
c segment
db 0,0,0,0,0,0,0,0
c ends
code segment
start: mov ax,a
mov es,ax
mov ax,b
mov ds,ax
mov bx,0
mov cx,8
s: mov ax,es:[bx]
add [bx],al
add bx,2
loop s
mov ax,c
mov es,ax
mov bx,0
mov cx,8
s1: mov ax,[bx]
mov es:[bx],ax
add bx,2
loop s1
mov ax,4c00h
int 21h
code ends
end start |