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主题 : : 〖分享我的实验9〗已调试通过,另类定义法,嵌套循环,这个没有写注释,如果你能看懂证明你很很很用功在学 [待解决] |
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注册日期:2011-02-07 19:07 |
assume cs:c,ds:d
d segment
db 'w',2,'e',2,'l',2,'c',2,'o',2,'m',2,'e',2,' ',2,'t',2,'o',2,' ',2,'m',2,'a',2,'s',2,'m',2,'!',2
db 'w',24h,'e',24h,'l',24h,'c',24h,'o',24h,'m',24h,'e',24h,' ',24h,'t',24h,'o',24h,' ',24h,'m',24h,'a',24h,'s',24h,'m',24h,'!',24h
db 'w',71h,'e',71h,'l',71h,'c',71h,'o',71h,'m',71h,'e',71h,' ',71h,'t',71h,'o',71h,' ',71h,'m',71h,'a',71h,'s',71h,'m',71h,'!',71h
d ends
c segment
k:
mov ax,d
mov ds,ax
mov ax,0b800h
mov es,ax
mov bx,0
mov bp,0
add bp,80
dec bp
sub bp,15
mov cx,11
x0:
add bp,160
loop x0
mov cx,3
x2:
mov dx,cx
mov si,0
mov cx,16
x1:
mov ax,[bx]
mov es:[bp][si],ax
add bx,2
add si,2
loop x1
add bp,160
mov cx,dx
loop x2
mov ax,4c00h
int 21h
c ends
end k | | |