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主题 : : 实验9.其实挺还好、不难 [待解决] |
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[帖 主]
[ 发表时间:2011-11-21 00:49 ]
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注册日期:2011-10-24 16:51 |
assume cs:code,ds:data,es:extra
data segment
db 'welcome to masm!'
data ends
extra segment
extra ends
code segment
start:
mov ax,data
mov ds,ax
mov ax,0b800h
mov es,ax
mov cx,16
mov bx,0
mov si,780h
s:mov al,[bx]
mov es:[si+24],al
mov es:[si+25],2h
add si,2
inc bx
loop s
mov bx,0
mov cx,16
mov si,820h
r:mov al,[bx]
mov es:[si+24],al
mov es:[si+25],00100100b
add si,2
inc bx
loop r
mov bx,0
mov cx,16
mov si,8c0h
q:mov al,[bx]
mov es:[si+24],al
mov es:[si+25],01110001b
add si,2
inc bx
loop q
mov ax,4c00h
int 21h
code ends
end start
end | | |
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[第1楼]
[ 回复时间:2011-11-21 19:00 ]
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注册日期:2008-01-19 14:51 |
是不难。楼主的这是一种思路,还可以将三个循环写成一个循环。 | | |
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[第2楼]
[ 回复时间:2012-08-20 17:08 ]
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注册日期:2012-08-14 17:57 |
楼主的程序又问题的:、
这是编译错误:
G:\try>masm 3.asm
Microsoft (R) Macro Assembler Version 5.00
Copyright (C) Microsoft Corp 1981-1985, 1987. All rights reserved.
Object filename [3.OBJ]:
Source listing [NUL.LST]:
Cross-reference [NUL.CRF]:
3.asm(22): error A2035: Operand must have size
3.asm(32): error A2035: Operand must have size
3.asm(42): error A2035: Operand must have size
50128 + 449904 Bytes symbol space free
0 Warning Errors
3 Severe Errors
G:\try> | | |
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[第3楼]
[ 回复时间:2012-10-10 14:36 ]
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注册日期:2012-10-10 14:30 |
22行 mov es:[si+25],2h 2h为立即数 不能直接传送 | | |
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[第4楼]
[ 回复时间:2012-12-25 13:05 ]
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注册日期:2012-12-25 12:34 |
搂主,,你这个应该不行。。。我给你该了下::
assume cs:code,ds:data,es:extra
data segment
db 'welcome to masm!'
data ends
extra segment
extra ends
code segment
start:
mov ax,data
mov ds,ax
mov ax,0b800h
mov es,ax
mov cx,16
mov bx,0
mov si,780h
s:mov al,[bx]
mov es:[si+24],al
mov ah,2h
mov es:[si+25],ah
add si,2
inc bx
loop s
mov bx,0
mov cx,16
mov si,820h
r:mov al,[bx]
mov es:[si+24],al
mov ah,00100100b
mov es:[si+25],ah
add si,2
inc bx
loop r
mov bx,0
mov cx,16
mov si,8c0h
q:mov al,[bx]
mov es:[si+24],al
mov ah,01110001b
mov es:[si+25],ah
add si,2
inc bx
loop q
mov ax,4c00h
int 21h
code ends
end start
end | | |
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[第5楼]
[ 回复时间:2013-03-12 22:10 ]
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注册日期:2013-03-04 06:21 |
mov al,[bx]
mov es:[si+24],al
mov ah,2h
mov es:[si+25],ah
可以改写成
mov al,[bx]
mov ah,2h
mov es:[si+24],ax | | |
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[第6楼]
[ 回复时间:2013-05-17 07:43 ]
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注册日期:2013-04-08 10:06 |
为什么你们的那么长-.- ??????????
assume cs:code
data segment
db 'w e l c o m e t o m a s m ! '
data ends
code segment
start: mov ax,data
mov ds,ax
mov ax,0b800H
mov es,ax
mov cx,16
mov bx,0
s: mov al,[bx]
mov es:[bx+64].8c0H,al
mov es:[bx+64].960H,al
mov es:[bx+64].0A00H,al
mov ah,00000010B ;或2h 写成2进制比较直观
mov es:[bx+65].8c0H,ah ;闪烁\背景R\G\B\高亮\前景R\G\B 1为开启 2为关闭
mov ah,01000010b ; 11111111B 则为闪烁高亮白字白背景
mov es:[bx+65].960H,ah
mov ah,01110001b
mov es:[bx+65].0A00H,ah
inc bx
inc bx
loop s
mov ax,4c00h
int 21h
code ends
end start | | |
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[第7楼]
[ 回复时间:2013-06-12 08:53 ]
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注册日期:2013-03-13 00:10 |
assume cs:code,ds:data
data segment
db 'welcome to masm!'
data ends
code segment
start: mov ax,data
mov ds,ax
mov ax,0b800h
mov es,ax
mov bx,0
mov si,0
mov di,1984
mov cx,16
s: mov ax,[si]
mov es:[bx+di],ax
mov byte ptr es:[bx+di+1],2h
add bx,160
mov ax,[si]
mov es:[bx+di],ax
mov byte ptr es:[bx+di+1],24h
add bx,160
mov ax,[si]
mov es:[bx+di],ax
mov byte ptr es:[bx+di+1],71h
inc si
add di,2
mov bx,0
loop s
mov ax,4c00h
int 21
code ends
end start | | |
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[第8楼]
[ 回复时间:2013-08-08 11:41 ]
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注册日期:2013-07-15 09:25 |
确实不难,用前7章知识参看实验材料就可以实现。
但实验目的是获得“编程经验”。学完第9章,感受到操纵CPU的手段在增强。通过在数据段设置值,来操纵代码的执行,完成实验9,有了一点“经验”,感觉真好! | | |
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