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主题 : : 实验7做出来了,最后人均收入感觉怪怪的,代码如下,请高手指点。。。。 [已解决] |
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[帖 主]
[ 发表时间:2011-02-28 22:46 ]
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assume cs:codesg
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
codesg segment
start: mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov bx,0
mov cx,21
mov si,0
mov di,0
s: mov ax,[si]
mov es:[bx],ax
mov ax,2[si]
mov es:2[bx],ax
mov ax,54h[si]
mov es:5[bx],ax
mov ax,56h[si]
mov es:7[bx],ax
mov ax,0a8h[di]
mov es:10[bx],ax
mov ax,54h[si]
div word ptr 0a8h[di]
mov es:13[bx],ax
add si,4
add di,2
add bx,16
loop s
mov ax,4c00h
int 21h
codesg ends
end start | | |
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[第1楼]
[ 回复时间:2011-03-07 02:28 ]
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我也发个看看
assume cs:code,ds:data,ss:stack
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
stack segment
dw 8 dup (0)
stack ends
code segment
start : mov ax,data
mov ds,ax
mov ax,stack
mov ss,ax
mov sp,16
mov ax,table
mov es,ax
mov bx,0 ;为年份和收入的地址变量?每次loop加4字节
mov si,0 ;为table表变量,每次loop加16字节
mov di,168 ;为人数地址变量,每次loop加2字节
mov cx,21
s:push cx ;后面有用到cx当除数所以在这保存
mov ax,[bx] ;输入年份
mov es:[si],ax
mov ax,2[bx]
mov es:2[si],ax
mov byte ptr es:4[si],' ' ;空格
mov ax,[bx+84] ;输入收入
mov es:5[si],ax
mov dx,2[bx+84] ;这里用dx因为后面当作被除数的高位
mov es:7[si],dx
mov byte ptr es:9[si],' '
mov cx,[di] ;输入人数,用CX因为当作除数
mov es:10[si],cx
mov byte ptr es:12[si],' '
div cx ;收入除以人数
mov es:13[si],ax
mov byte ptr es:15[si],' '
add si,16
add bx,4
add di,2
pop cx
loop s
mov ax,4c00h
int 21h
code ends
end start | | |
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[第2楼]
[ 回复时间:2011-03-07 02:31 ]
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结果如下
0B61:0000 31 39 37 35 20 10 00 00-00 20 03 00 20 05 00 20 1975 .... .. ..
0B61:0010 31 39 37 36 20 16 00 00-00 20 07 00 20 03 00 20 1976 .... .. ..
0B61:0020 31 39 37 37 20 7E 01 00-00 20 09 00 20 2A 00 20 1977 ~... .. *.
0B61:0030 31 39 37 38 20 4C 05 00-00 20 0D 00 20 68 00 20 1978 L... .. h.
0B61:0040 31 39 37 39 20 56 09 00-00 20 1C 00 20 55 00 20 1979 V... .. U.
0B61:0050 31 39 38 30 20 40 1F 00-00 20 26 00 20 D2 00 20 1980 @... &. ..
0B61:0060 31 39 38 31 20 80 3E 00-00 20 82 00 20 7B 00 20 1981 .>.. .. {.
0B61:0070 31 39 38 32 20 A6 5F 00-00 20 DC 00 20 6F 00 20 1982 ._.. .. o.
0B61:0080 31 39 38 33 20 91 C3 00-00 20 DC 01 20 69 00 20 1983 .... .. i.
0B61:0090 31 39 38 34 20 C7 7C 01-00 20 0A 03 20 7D 00 20 1984 .|.. .. }.
0B61:00A0 31 39 38 35 20 81 24 02-00 20 E9 03 20 8C 00 20 1985 .$.. .. ..
0B61:00B0 31 39 38 36 20 8A 03 03-00 20 A2 05 20 88 00 20 1986 .... .. ..
0B61:00C0 31 39 38 37 20 7C 47 05-00 20 D2 08 20 99 00 20 1987 |G.. .. ..
0B61:00D0 31 39 38 38 20 EB 03 09-00 20 E9 0A 20 D3 00 20 1988 .... .. ..
0B61:00E0 31 39 38 39 20 CA 42 0C-00 20 C5 0F 20 C7 00 20 1989 .B.. .. ..
0B61:00F0 31 39 39 30 20 18 0D 12-00 20 03 16 20 D1 00 20 1990 .... .. ..
0B61:0100 31 39 39 31 20 38 1F 1C-00 20 22 20 20 E0 00 20 1991 8... " ..
0B61:0110 31 39 39 32 20 58 19 2A-00 20 16 2D 20 EF 00 20 1992 X.*. .- ..
0B61:0120 31 39 39 33 20 28 44 39-00 20 5E 38 20 04 01 20 1993 (D9. ^8 ..
0B61:0130 31 39 39 34 20 28 F0 46-00 20 99 3B 20 30 01 20 1994 (.F. .; 0.
0B61:0140 31 39 39 35 20 68 97 5A-00 20 88 45 20 4D 01 20 1995 h.Z. .E M. | | |
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[第3楼]
[ 回复时间:2011-03-07 02:38 ]
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楼主这里错了:
mov ax,54h[si]
div word ptr 0a8h[di]
mov es:13[bx],ax
被除数要ax和dx | | |
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[第4楼]
[ 回复时间:2011-03-08 22:28 ]
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注册日期:2010-12-01 18:59 |
此贴由 贴主 于 [ 2011-03-08 22:28 ] 结贴。 结贴原因:问题已解决 | | |
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