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主题 : : 虽然有点烦杂,第8章实验7还是完成了.....(暂没加代码说明,不会加) [已解决] |
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[帖 主]
[ 发表时间:2009-11-12 14:27 ]
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注册日期:2009-10-21 20:01 |
assume cs:codesg,ds:data,es:table
data segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd
16,22,382,1356,2390,8000,16000,24486,50065,97479,14017,197514
dd
345980,590827,803530,1183000,1843000,2759000,3753000,4649000,593
7000
dw
3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15257,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
stack segment
dw 0,0,0,0,0,0,0,0
stack ends
codesg segment
start:mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov ax,stack
mov ss,ax
mov sp,16
mov bx,0
mov di,0
mov cx,21
s0:push cx
mov si,0
mov cx,4
s1:mov dl,[di]
mov es:[bx+si+0h],dl
mov dl,[di+54h]
mov es:[bx+si+5h],dl
inc di
inc si
loop s1
pop cx
add bx,10h
loop s0
mov cx,21
mov bx,0
mov di,0
s2:push cx
mov si,0
mov cx,2
s3:mov dl,[di+0A8h]
mov es:[bx+si+0Ah],dl
inc di
inc si
loop s3
mov ax,ds:[bp+54h]
mov dx,ds:[bp+56h]
div word ptr es:[bx+si+8h]
mov es:[bx+si+0Bh],ax
add bp,4
pop cx
add bx,10h
loop s2
mov ax,4c00h
int 21h
codesg ends
end start | | |
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[第1楼]
[ 回复时间:2009-11-13 13:15 ]
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注册日期:2009-11-05 15:19 |
我来贴个栈命令的
实验七
assume cs:code,ds:data,es:table
data segment
year db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
salary dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
employer dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11542,14430,15275,17800
data ends
table segment
db 21 dup ('year summ ne ?? ')
table ends
code segment
start: mov ax,data
mov ds,ax
mov ax,table
mov es,ax
mov si,0
mov di,0
mov bx,0
mov cx,21
s: push word ptr [year+si]
push word ptr [year+si+2]
push word ptr [salary+si]
push word ptr [salary+si+2]
push word ptr [employer+di]
pop es:[bx+0ah]
pop es:[bx+7]
pop es:[bx+5]
pop es:[bx+2]
pop es:[bx+0]
mov dx,word ptr [salary+2]
mov ax,word ptr [salary]
div word ptr es:[bx+0ah]
mov es:[bx+0eh],ax
add bx,16
add di,2
add si,4
loop s
mov ax,4c00h
int 21
code ends
end start
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名字用起来就是爽,不用自己去数数。 | | |
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[第2楼]
[ 回复时间:2009-11-13 22:37 ]
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注册日期:2009-09-24 23:25 |
楼上方法好先进呀。
栈可以用到这种地步,还不明白可以试出来不能,得试一下。感觉有些问题呀。得试试再说。 | | |
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[第3楼]
[ 回复时间:2009-11-13 23:20 ]
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注册日期:2009-09-24 23:25 |
虽然没有进行实验,不过我体会到了楼上得法的精妙呀,强呀。多学习一下。谢谢了。 | | |
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[第4楼]
[ 回复时间:2009-11-13 23:23 ]
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楼主的算法很实在呀,是我们思考的路径,一般都会这样的。我想过了几种算法,包括楼上的两种,还有一种,不过均写不出程序,郁闷呀。呵呵。 | | |
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[第5楼]
[ 回复时间:2009-12-03 16:14 ]
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注册日期:2009-10-21 20:01 |
此贴由 贴主 于 [ 2009-12-03 16:14 ] 结贴。 结贴原因:问题已解决 | | |
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