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主题 : : 新人来提交实验7的答案，没有使用栈 [待解决] |
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[帖 主]
[ 发表时间：2019-08-22 12:57 ]
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注册日期：2010-11-21 12:54 |
assume cs:codesg,ds:datasg,es:table
datasg segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11452,14430,15257,17800
datasg ends
table segment
db 21 dup('year summ ne ?? ')
table ends
codesg segment
start: mov ax,datasg
mov ds,ax
mov ax,table
mov es,ax
mov bp,0
mov bx,0
mov si,0
mov cx,21
s: mov ax,ds:0[bx]
mov es:[bp],ax
mov ax,ds:2[bx]
mov es:[bp+2],ax ;年份
mov ax,ds:168[si]
mov es:10[bp],ax ;人数
mov ax,84[bx]
mov es:5[bp],ax
mov dx,86[bx]
mov es:7[bp],dx ;收入，和“年份”结构一样
div word ptr es:10[bp] ;平均收入=收入/人数
mov es:13[bp],ax
add bx,4
add si,2
add bp,16
loop s
mov ax,4c00h
int 21h
codesg ends
end start | | |
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[第1楼]
[ 回复时间：2019-08-26 00:01 ]
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注册日期：2010-11-21 12:54 |
assume cs:codesg,ds:datasg,ss:stack
datasg segment
db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
db '1993','1994','1995'
dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000
dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
dw 11452,14430,15257,17800
datasg ends
stack segment
dw 32 dup (0)
stack ends
table segment
db 21 dup('year summ ne ?? ')
table ends
codesg segment
start: mov ax,datasg
mov ds,ax
mov ax,stack
mov ss,ax
mov sp,32
mov ax,table
mov es,ax
mov di,0
mov si,0
mov cx,21
s1: push cx
mov cx,2
mov bx,0
s: mov ax,ds:[di]
mov es:[si+bx],ax ;每次移动2字节
add bx,2
add di,2
loop s ;每行循环两次
pop cx
add si,10h
loop s1 ;以上录入年份
mov cx,21
mov di,0
mov si,0
s2: mov ax,ds:[di].168
mov es:[si].10d,ax
add di,2
add si,10h
loop s2 ;以上录入人数
mov cx,21
mov di,0
mov si,0
s3: mov ax,ds:[di].84d
mov es:[si].5d,ax
mov dx,ds:[di].86d
mov es:[si].7d,dx ;以上录入工资
mov bx,es:[si].10d
div bx ;(dx,ax)/bx=ax...dx
mov es:[si].13d,ax ;录入人均收入
add di,4
add si,10h
loop s3
mov ax,4c00h
int 21h
codesg ends
end start | | |
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