assume cs:code,ss:stack
stack segment
dw 16 dup (0)
stack ends
data segment
Y db 32 dup (0),13,10,'$'
data ends
code segment
start: mov ax,data
mov ds,ax
mov ax,12345
mov bx,0
mov cx,0
mov di,0
mov si,0
call s
mov dx,0
mov ax,seg Y
mov ds,ax
lea dx,Y
mov ah,9
int...
[2009-05-16 20:42] 自己写的2进制转换十进制
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[2009-05-14 21:34] 实验十二 修改了一阵子也搞定~
代码如下:
assume cs:code
code segment
start: mov ax,cs
mov ds,ax
mov si,offset do0
mov ax,0
mov es,ax
mov di,200h
mov cx,offset do0end-offset do0
cld
rep movsb
mov ax,0
mov es,ax
mov word ptr es:[0*4],200h
mov word ptr es:[0*4+2],0
mov ax,0f000h
mov dx,22d
mov cx,...
assume cs:code
code segment
start: mov ax,cs
mov ds,ax
mov si,offset do0
mov ax,0
mov es,ax
mov di,200h
mov cx,offset do0end-offset do0
cld
rep movsb
mov ax,0
mov es,ax
mov word ptr es:[0*4],200h
mov word ptr es:[0*4+2],0
mov ax,0f000h
mov dx,22d
mov cx,...
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[2009-05-13 13:18] 第11章 实验11 轻松写出来啦~
代码如下:
assume cs:codesg
datasg segment
db "Beginner's All-purpose Symbolic Instruction Code.",0
datasg ends
codesg segment
begin: mov ax,datasg
mov ds,ax
mov si,0
mov cx,0
call letterc
mov ax,4c00h
int 21h
letterc: mov cx,[si]
...
assume cs:codesg
datasg segment
db "Beginner's All-purpose Symbolic Instruction Code.",0
datasg ends
codesg segment
begin: mov ax,datasg
mov ds,ax
mov si,0
mov cx,0
call letterc
mov ax,4c00h
int 21h
letterc: mov cx,[si]
...
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